Newton's Law Of Motion

| Explain the concept of inertia |
| Inertia is the ability of a resting body to resist motion or a moving body to continue moving in a |
| straight line when abruptly stopped. |
| The more mass a body has, the greater its inertia and vice versa is true. |
| Newton's First Law of Motion |
| State Newton's first law of Motion |
| Newton’s 1st law of motion states that |
| “Everybody will continue in its state of rest or of |
| uniform motion unless an external force acts upon it” |
| Verification of Newton's First Law of Motion |
| Verify Newton's first law of Motion |
| To verif y Newton’s 1st law of motion. |
| Glass, manila card and small coin. |
| A small coin is placed on a manila card and the card is positioned on top of the glass such that |
| the coin is directly positioned over the open mouth of the bottle. |
| Flick the card at C. Make sure that the card is not tilted by moving the finger in the horizontal |
| When the card is flicked away quickly by finger, the coin drops neatly into the |
| glass. The coin dropped into the glass because there was no force applied on it when the card |
| The coin continued to be at rest as the card was flicked quickly. This experiment |
| verify Newton’s 1st law of motion. |
| The Concept of Linear Momentum |
| Explain concept of linear momentum |
| Linear momentum of a body is the product of mass and velocity of that body. |
| Momentum = Mass, m x Velocity, v |
| The SI Unit of Linear Momentum |
| State the SI unit of linear momentum |
| The unit of momentum is kilogram meter per second(kgm/s) |
| Determine linear momentum |
| When two bodies, a heavy one and the light one are acted upon by an external force at the same |
| time(collide) the light body builds up a higher velocity than the heavy one but the momentum |
| they gain remain the same in both cases. |
| i.e Momentum before collision = Momentum after collision. This is what we call the |
| conservation of momentum and is described by Newton’s 2nd law of motion. |
| Newton's Second Law of Motion |
| State Newton's second law of Motion |
| Newton’s 2nd law of motion states that |
| “The rate of change of momentum is proportional to |
| the applied force and it takes place in the direction of a force” |
| Consider a body of mass, (m) acted by an external force (f) from an initial velocity (u) to the |
| final velocity (v) within a time interval (t). |
| Change of momentum = mv – mu |
| Hence the Newton’s 2nd law of motion can be summarized as; |
| “The force is directly proportional to acceleration of the object and the acceleration of the |
| same body is inversely proportional to its mass” |
| If a mass of 1kg is accelerated with an acceleration of 1m/sÇ then the force of 1N is said to be |
| is the force which when acting on a body of mass 1kg it produces an acceleration of |
| Verification of Newton's Second Law of Motion |
| Verify Newton's second law of Motion |
| A trolley experiences an acceleration when an external force is applied to it. The aim of this |
| datalogging experiment is explore the relationship between the magnitudes of the external force |
| and the resulting acceleration. |
| Light gate, interface and computer |
| Double segment black card (see diagram) |
| Take care when masses fall to the floor. Use a box or tray lined with bubble wrap (or similar) |
| under heavy objects being lifted. This will prevent toes or fingers from being in the danger zone. |
| Select the falling mass to be 100 g. Pull the trolley back so that the mass is raised to just |
| below the pulley. Position the light gate so that it will detect the motion of the trolley soon after |
| it has started moving.Set the software to record data, then release the trolley. Observe the |
| measurement for the acceleration of the trolley. |
| Repeat this measurement from the same starting position for the trolley several times. |
| Enter from the keyboard '1'( 1 newton) in the force column of thetable. |
| Transfer 100 g from the trolley to the slotted mass, to increase it to 200 g. Release the |
| trolley from the same starting point as before. Repeat this several times. Enter '2' (2 newtons) in |
| the force column of the table. |
| Repeat the above procedure for slotted masses of 300 g and 400 g. |
| Conservation of linear Momentum |
| Difference between Elastic and Inelastic Collisions |
| Distinguish between Elastic and Inelastic Collisions |
| This is the type of collision whereby each body moves with a separate velocity after collision. In |
| this type of collision both energy and momentum are conserved. |
| Is the type of collision whereby all bodies move with the same velocity after collision. This |
| velocity is known as common velocity. In this type of collision energy is not conserved, only |
| is the change of momentum which is given asm the product of force and the time taken |
| F = mv – mu –Ft is the impulse of a force which is given by mv – mu. |
| The Principle of Conservation of Linear Momentum |
| State the principle of conservation of linear Momentum |
| “When two or more bodies acts upon |
| Principle of conservation of linear momentum states that, |
| one another; that is when they collide their total momentum remains constant, provided that |
| there is no external force acting” |
| Momentum before collision = Momentum after collision |
| Consider two bodies of masses m |
| moving with initial velocities u |
| move with final velocities v |
| respectively after they collide one another. |
| From the principle of conservation of momentum: Momentum before collision = Momentum |
| The Principle of Conservation of Linear Momentum in Solving Problems |
| Apply the principle of conservation of linear momentum in solving problems |
| Apply the principle of conservation of linear momentum in solving problems |
| Difference between Action and Reaction Forces |
| Distinguish between Action and Reaction Forces |
| Consider a book of mass, m which is at rest on a table. This book will exert on a table with a |
| force equal to its weight. The table exert an equal upward force. |
| The downward force exerted by the book(weight) on the table is known as action force while the |
| upward force exerted by the table on the book is known as reaction force. |
| These two forces acts in opposite direction but they are equal in magnitude. |
| Where; R = reaction, mg=weight of a book |
| Newton's Third Law of Motion |
| State Newton's third Law of Motion |
| Newton’s 3rdlaw of motionstates that |
| “To every action there is an equal and opposite reaction” |
| Application of Newton's Third Law of Motion |
| Apply Newton's third Law of Motion |
| The person firing a gun will feel the recoil when the bullet leaves the gun. |
| Consider a gun of mass mg ejects a bullet of mass mb with a velocity vb and the gun recoils with |
| From the principle of conservation of momentum: |
| Recoil momentum of gun = Momentum of bullet |
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